The displacement (in metre) of a particle moving along X-axis is given by x = 18 t + 5t 2 .
Calculate (i) The instantaneous velocity at t = 2s,
(ii) average velocity between t = 2s and t = 3s,
(iii) Instantaneous acceleration
Text Solution
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CHECK THE SOLUTION
Sol. x = 18t + 5t 2
v = 
= 18 + 10t
At t = 2s, v = 18 + 10 × 2 = 38 ms –1
a = 
= 10 (a constant)
v av = 
i.e., v av = 
= 
= 43 ms –1 .
(iii) acceleration = 10 ms –2
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